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26-31x+7x^2=0
a = 7; b = -31; c = +26;
Δ = b2-4ac
Δ = -312-4·7·26
Δ = 233
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-31)-\sqrt{233}}{2*7}=\frac{31-\sqrt{233}}{14} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-31)+\sqrt{233}}{2*7}=\frac{31+\sqrt{233}}{14} $
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